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QiShunwang

“诚信为本、客户至上”

pytyon 带有重复的全排列

2021/6/3 17:30:02   来源:
复制代码 代码如下:

from sys import argv
script, start, end = argv
vis = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
ans = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
def dfs(cur, m):
 ans[cur] = m
 if cur == int(end) - int(start) + 1:
  for i in xrange(int(start), int(end) + 1):
   print ans[i],
  return
 cur = cur + 1
 for i in xrange(int(start), int(end) + 1):
  dfs(cur, i)
  print
dfs(0, start)